Revista Mexicana Ciencias Agrícolas volume 13 number 2 February 15 - March 31, 2022
DOI: https://doi.org/10.29312/remexca.v13i2.3130
Article
Use of artifices in Opstat to analyze series of experiments in a partial diallel
Delfina de Jesús Pérez-López1
Gerardo Jasso-Bobadilla1
Claudia Saavedra-Guevara2
J. Ramón Pascual Franco-Martínez2
José Francisco Ramírez-Dávila1
Andrés González-Huerta1§
1Center for Research and Advanced Studies in Plant Breeding-Faculty of Agricultural Sciences. AP. 435. Tel. 722 2965518, ext. 148. (djperezl@uaemex.mx; gjassob105@alummo.uaemex.mx; jframirezd@uaemex.mx). 2Doctoral Program in Agricultural Sciences and Natural Resources-Institute of Agricultural and Rural Sciences. University Campus ‘El Cerrillo’-Autonomous University of the State of Mexico, Toluca, State of Mexico. Tel. 722 2965552, ext. 117. (csaavedrag001@alumno.uaemex.mx; jrfrancom@uaemex.mx).
§Corresponding author: agonzalezh@uaemex.mx.
Abstract
The use of specialized software saves time and resources when designing, randomizing and analyzing diallel cross experiments in a plant breeding program. In this study, the components of an analysis of variance (Anova) are calculated for a series of experiments in a randomized complete block design applied to the grain yield of a partial diallel cross generated with eight lines of corn (Zea mays L.), each sampled five times (p= 8; s= 5), evaluated in three environments and in four repetitions per environment (n= 240 data). The main objective was to validate these results with the Opstat statistical package, which produces the Anova outputs for each trial and some indirect calculations to complete this in the series of experiments. The most critical part of the statistical genetic analysis was to propose an artifice to decompose the effects of GCA and SCA in the crosses and those corresponding to GCA x A and SCA x A in the interaction crosses x environments. In these calculations, the inverse of the matrix A is common in all operations performed with matrix algebra. In the above context, it was observed that Opstat is very friendly and reliable to generate the Anovas and gi estimators for the evaluated parents, but it incorrectly calculates narrow-sense heritability when some negative variance is estimated.
Keywords: circulating matrices, free software, randomized complete block design, symmetrical incomplete diallel.
Reception date: December 2021
Acceptance date: February 2022
Introduction
The design and analysis of a partial diallel cross necessarily leads to a series of experiments in time, space, or both (Dhillon, 1978; Martínez, 1983, 1991; González et al., 2007). In agricultural sciences, it is common to evaluate genetic material in several years, different localities or multiple environments formed by them (Gomez and Gomez, 1984; González et al., 2019). The generation, validation, application and transfer of technology also depends on this type of planning when, in factorial trials, it is desired to evaluate a set of genotypes on planting dates, population densities, fertilization formulas, pesticide doses or tillage methods, among others (Torres et al., 2017; Padilla et al., 2019; González et al., 2019; Pérez et al., 2021).
The partial diallel cross was created as an option to Griffing’s (1956) method 4, because it presents serious limitations when the number of parents that will be used in the crosses increases (Kempthorne and Curnow, 1961; Mastache et al., 1998; Saavedra et al., 2021), which would make their evaluation unmanageable and impractical, particularly in multiple environments (Dhillon, 1978; Martínez, 1983, 1991; Jasso et al., 2022). In a partial diallel experiment, circulating matrices with special mathematical properties are used, but when using a desktop calculator is used, it is very laborious to obtain its inverse and the estimates that involve it (Martínez, 1991; Jasso et al., 2022).
The use of a matrix calculator or a specialized statistical package, preferably free, is very desirable and necessary to analyze this type of trials; some options are Opstat (Jasso et al., 2022), Statistical Analysis System (SAS; Martínez, 1991; Mastache and Martínez, 1998) or Genes (Cruz, 2013), although with these it is not possible to generate an analysis of variance (Anova) for the series of experiments (Jasso et al., 2022).
In the present study, calculations are performed to obtain the Anova of a partial diallel evaluated in three environments under a randomized complete block design using grain yield data from corn crosses formed with eight inbred lines, sampled five times each; in each environment (A) four repetitions were used. To complete the Anova table, the effects of general and specific combining ability (GCA and SCA) for parents and crosses, respectively, as well as those of GCA x A and SCA x A, were obtained from the genetic analysis generated by Opstat applying an artifice to the data concentrated in a table of values crosses x environments (CxA), averaged over repetitions; the inverse of the matrix A is common in all calculations involving matrix algebra. Based on the above, the objective of the present study was to design some artifices to obtain and validate with Opstat the results presented in this study.
Algebraic procedures
The sums of squares of crosses will be split into GCA and SCA; then, the interaction crosses x environments (C x A) will be fractionated into GCA x A and SCA x A. It will be considered t= (ps/2) = 20 crosses (p=8, s=5), where p and s are the number of parents and times each of these participates in the partial diallel, respectively. Totals or arithmetic means can be used in calculations (Kempthorne and Curnow, 1961; Dhillon, 1978; Martínez, 1983; Mastache et al., 1998).
Statistical models
One environment: Yijk= μ + Cij + Rk + Eijk, multiple environments: Yijkl = µ + Ak + Cij + (AC)ijk + Rl(k) + Eijkl.
Genetic models
One environment: Yijk= µ + [gi + gj + Sij] + Rk + Eijk, Multiple environments: Yijkl = µ + Ak +[gi + gj+ Sij] + [(gl)ik + (gl)jk +(Sl)ijk] + Rl(k) + Eijkl. Where: μ is the population arithmetic mean; gi, gj are the effects of GCA in parents; Sij are the effects of SCA in crosses; Ak is the contribution of the k-th environment; (gl)ik, (gl)jk are the interaction effects GCA x A; (Sl)ijk is the interaction SCA x A; Rl, Rl(k) are the effects of repeats and repeats nested within environments; Eijk, Eijkl are the residuals of the models (Dhillon, 1978; Jasso et al., 2022), in which Martínez (1983) and Mastache et al. (1998) imposed the restriction nij= 1 or nij= 0 whether or not the cross ixj is included, respectively. Jasso et al. (2022) also introduced the restriction i< j, as well as ixj ≠ of crosses that complete, along with the partial diallel, Griffing’s (1956) method 4.
General variance analysis
The design of the crosses and the Anova for one trial was shown by Jasso et al. (2022). For the Anova of the series of experiments, the following stages will be applied: Stage 1. Construct Table 1; generate the Anova for each trial and obtain the sums of squares of repetitions within environments and the combined error (Gomez and Gomez, 1984).
Table 1. Grain yield (t ha-1) of 20 corn crosses evaluated in three environments.
Crosses (ij) | Environments (k) | |||||||||||||
A1 | A2 | A3 | ||||||||||||
R1 | R2 | R3 | R4 | R1 | R2 | R3 | R4 | R1 | R2 | R3 | R4 | |||
1) 1x3 | 9.25 | 5.46 | 5.62 | 7.14 | 3.64 | 7.64 | 6.46 | 6.19 | 10.96 | 10.52 | 8.48 | 9.14 | ||
2) 1x4 | 9.56 | 8.4 | 6.27 | 5.56 | 6.31 | 6.91 | 8.02 | 7.43 | 10.37 | 11 | 9.52 | 11.04 | ||
3) 1x5 | 6.87 | 7.71 | 5.56 | 6.73 | 5.81 | 6.89 | 8.02 | 7.12 | 8.44 | 8.7 | 10.06 | 7.50 | ||
4) 1x6 | 8.87 | 7.75 | 6.75 | 6.46 | 7.54 | 5.48 | 6.98 | 7.96 | 9.73 | 7.85 | 9.27 | 11.29 | ||
5) 1x7 | 8.46 | 8.23 | 6.1 | 6.54 | 5.41 | 6.73 | 6.83 | 7.31 | 9.33 | 11.08 | 8.41 | 8.66 | ||
6) 2x4 | 9.77 | 8.77 | 7.35 | 6.77 | 5.35 | 7.29 | 7.81 | 7.21 | 8.64 | 9.14 | 10.5 | 8.43 | ||
7) 2x5 | 8.31 | 8.46 | 7.23 | 5.79 | 5.64 | 8.29 | 7.02 | 6.37 | 9.75 | 8.25 | 10.46 | 10.08 | ||
8) 2x6 | 6.98 | 5.85 | 6.68 | 5.08 | 5.68 | 6.52 | 6.87 | 6.79 | 7.83 | 5.3 | 9.16 | 8.66 | ||
9) 2x7 | 7.75 | 8.18 | 6.45 | 6.87 | 7.35 | 6.25 | 7.43 | 8.02 | 9.93 | 7.54 | 9.23 | 10.31 | ||
10) 2x8 | 7.25 | 6.18 | 6.14 | 5.75 | 6.06 | 8.23 | 7.12 | 6.91 | 11.2 | 9.39 | 9.06 | 10.38 | ||
11) 3x5 | 7.6 | 6.12 | 6.91 | 8.16 | 5 | 6.1 | 5.14 | 4.96 | 10.43 | 8.77 | 10.52 | 8.58 | ||
12) 3x6 | 7.44 | 6.58 | 5.7 | 7.79 | 5.93 | 6.25 | 7.25 | 8.12 | 8.77 | 11.12 | 7.83 | 8.33 | ||
13) 3x7 | 7.85 | 7.1 | 4.79 | 6.71 | 7.41 | 6.6 | 6.46 | 3.79 | 7.71 | 8.31 | 6.81 | 8.35 | ||
14) 3x8 | 8.6 | 6.93 | 6.16 | 6.91 | 7.41 | 5.89 | 6.98 | 6.08 | 7.52 | 9.81 | 8.23 | 7.7 | ||
15) 4x6 | 8.04 | 7.73 | 5.23 | 4.62 | 5.54 | 7.02 | 6.27 | 6.46 | 9.06 | 8.98 | 7.46 | 8.89 | ||
16) 4x7 | 6.21 | 7.12 | 6.16 | 5.5 | 6.93 | 7.91 | 6.5 | 7.23 | 7.7 | 10.12 | 8.1 | 7.43 | ||
17) 4x8 | 8.64 | 5.5 | 7.04 | 7.68 | 6.39 | 5.62 | 5.14 | 6.79 | 11.2 | 11.66 | 8.33 | 8.12 | ||
18) 5x7 | 7.37 | 4.18 | 4.46 | 4.99 | 6.58 | 9.64 | 4.37 | 6.56 | 7.2 | 7.89 | 7.79 | 6.85 | ||
19) 5x8 | 5.62 | 6.46 | 6.46 | 4.58 | 5 | 7.12 | 6.32 | 6.29 | 7.52 | 9.41 | 8.62 | 7 | ||
20) 6x8 | 7.62 | 6.43 | 6.23 | 6.66 | 7.14 | 4.37 | 6.66 | 6.5 | 7.87 | 6.77 | 8.18 | 7.81 |
Environments= A1, A2, A3; repetitions = R1, R2, R3, R4.
Stage 2. Calculate degrees of freedom (DF)
DF of the Total= [ar(ps/2)] - 1= 3(4)(20) - 1= 239; DF Environments (A)= a -1= 2; DF Rep(A)= a(r-1)= 3(3)= 9. For verification: DF Trat 1= DF A + DF Rep(A)= ar - 1, then: DF Rep(A)= DF Trat 1 - DF A= (ar - 1) - (a - 1)= ar -1 - a + 1= a(r-1)= 9; DF Crosses (C)= (ps/2) - 1= [(8) (5)/2] - 1= 19; DF C x A= [(ps/2) - 1] (a-1)= 19(2)= 38; DF Error= DF Total - DF A - DF Rep (A) - DF C - DF C x A= 239 - 2 - 9 - 19 - 38= 171. Also: DF Error= a(r-1) [(ps/2) - 1]= 3(3) (19)= 171. For verification: DF Error= {[a(ps/2)r] - 1} - (a -1) - a(r-1)- [(ps/2) - 1] - {[(ps/2) - 1] (a-1)}= [a(ps/2)r] - 1 - a + 1 - ar + a - (ps/2) + 1 - (aps/2) + a + (ps/2) -1= (apsr/2) - ar - a(ps/2) + a= a[(psr)/2) - r - (ps/2) + 1 ]= a(r-1) [(ps/2) - 1].
Stage 3. Obtain sums of squares (SS)
SS A (k=3) = =
SS C (ij=20) = = = 62.35
To calculate SS C x A, one first defines SS Trat 1 = SS A + SS C + SS C x A, where: SS Trat 1(ijk=60) =
SS C x A (ijk= 60)= SS Trat 1 - SS A - SS C= 374.38 - 260.94 - 62.35= 51.09
SS Rep (A)==SS RepA1 +SS RepA2 +SS RepA3= 1.765+6.34+37.52= 45.625
Table A x Rep allows verifying the previous calculation (Table 2) and the procedure shown below is very useful to calculate the contribution of any interaction, in this and in other factorial experiments (Padilla et al., 2019; González et al., 2019; Pérez et al., 2021).
Table 2. Data to calculate SS Rep (A).
Environments (.k) | Repetitions (l) | Total | ||||
R1 | R2 | R3 | R4 | Y..k. | ||
A.1 | 158.06 | 139.14 | 123.29 | 126.29 | 546.78 | |
A.2 | 122.12 | 136.75 | 133.65 | 134.09 | 526.61 | |
A.3 | 181.16 | 181.61 | 176.02 | 174.55 | 713.34 | |
Total | 461.34 | 457.5 | 432.96 | 434.93 | 1786.73 |
SS TRAT 2(kl=12)= SS A + SS Rep (A)= = 308.35
SS A = =
SS Rep (A)= SS Trat 2 - SS A = 308.35 - 262.57= 45.78
SS Error== SSErrorA1 + SSErrorA2 + SSErrorA3 = 46.32 + 61.53 + 73.88= 181.73
SS Total= SS A + SS Rep (A) + SS C + SS CxA + SS Error= 601.75
Also: SS Total(ijkl=240)= = 601.75
Stage 4. Break down DF and SS of crosses into GCA and SCA
DF GCA= p - 1= 7; DF SCA= DF Crosses - DF GCA= 19 - 7= 12. Also: DF SCA= [(ps/2) - 1] - (p - 1) = (ps/2) - 1 - p +1= (ps - 2p)/2= p (s-2)/2= 8(3)/2= 12
Similarly to the case of individual trials, in the series of experiments: SS GCA = ; where: Qi = ) y =
The correction factor for crosses is CFQ = ; aij or A-1 is the inverse of the matrix Apxp = [sI + N] = [aij], Qj forms a column vector (H) and generates another column vector (G), in the latter its solution is: G = A-1 H (Jasso et al., 2022). Qi values are calculated using the data in Table 3.
Table 3. Data to calculate the interaction CxA.
No. | Crosses (ij) | Environments (k) | Total (Yij..) | Means | |||||||
A1 | A2 | A3 | |||||||||
Yij1. | Yij2. | Yij3. | |||||||||
1 | 1 x 3 | 27.48 | 6.87 | 23.92 | 5.98 | 39.08 | 9.77 | 90.48 | 7.54 | ||
2 | 1 x 4 | 29.8 | 7.45 | 28.68 | 7.17 | 41.92 | 10.48 | 100.4 | 8.36 | ||
3 | 1 x 5 | 26.88 | 6.72 | 27.84 | 6.96 | 34.68 | 8.67 | 89.4 | 7.45 | ||
4 | 1 x 6 | 29.84 | 7.46 | 27.96 | 6.99 | 38.12 | 9.53 | 95.92 | 7.99 | ||
5 | 1 x 7 | 29.32 | 7.33 | 26.28 | 6.57 | 37.48 | 9.37 | 93.08 | 7.76 | ||
6 | 2 x 4 | 32.64 | 8.16 | 27.64 | 6.91 | 36.72 | 9.18 | 97 | 8.08 | ||
7 | 2 x 5 | 29.84 | 7.46 | 27.32 | 6.83 | 38.52 | 9.63 | 95.68 | 7.97 | ||
8 | 2 x 6 | 24.6 | 6.15 | 25.84 | 6.46 | 30.96 | 7.74 | 81.4 | 6.78 | ||
9 | 2 x 7 | 29.24 | 7.31 | 29.04 | 7.26 | 37 | 9.25 | 95.28 | 7.94 | ||
10 | 2 x 8 | 25.32 | 6.33 | 28.32 | 7.08 | 40.04 | 10.01 | 93.68 | 7.8 | ||
11 | 3 x 5 | 28.8 | 7.2 | 21.2 | 5.3 | 38.28 | 9.57 | 88.28 | 7.36 | ||
12 | 3 x 6 | 27.52 | 6.88 | 27.56 | 6.89 | 36.04 | 9.01 | 91.12 | 7.59 | ||
13 | 3 x 7 | 26.44 | 6.61 | 24.24 | 6.06 | 31.16 | 7.79 | 81.84 | 6.82 | ||
14 | 3 x 8 | 28.6 | 7.15 | 26.36 | 6.59 | 33.24 | 8.31 | 88.2 | 7.35 | ||
15 | 4 x 6 | 25.6 | 6.4 | 25.28 | 6.32 | 34.4 | 8.6 | 85.28 | 7.1 | ||
16 | 4 x 7 | 25 | 6.25 | 28.56 | 7.14 | 33.36 | 8.34 | 86.92 | 7.24 | ||
17 | 4 x 8 | 28.84 | 7.21 | 23.92 | 5.98 | 38.8 | 9.7 | 91.56 | 7.63 | ||
18 | 5 x 7 | 21 | 5.25 | 27.16 | 6.79 | 29.72 | 7.43 | 77.88 | 6.48 | ||
19 | 5 x 8 | 23.12 | 5.78 | 24.72 | 6.18 | 32.56 | 8.14 | 80.4 | 6.7 | ||
20 | 6 x 8 | 26.92 | 6.73 | 24.64 | 6.16 | 30.64 | 7.66 | 82.2 | 6.85 | ||
546.8 | 526.48 | 712.72 | 1786 |
Q1= (Y13..- CFQ) + (Y14..- CFQ) + (Y15.. - CFQ) + (Y16.. - CFQ) + (Y17.. - CFQ); CFQ= 2(1786)/40= 89.3. Q1= (90.48 - 89.3) + (100.4 - 89.3) + (89.4 - 89.3) + (95.92 - 89.3) + (93.08 - 89.3)= 22.78. Likewise: Q2= 16.54; Q3= -6.58; Q4= 14.66; Q5= -14.86; Q6= -10.58; Q7= -11.5; Q8= -10.46. The sum over Qi is zero and the GCA estimators for parents () are calculated as:= =
= =
With this information, one carries out the breakdown of the SS of crosses into
SS GCA=( Q1 + Q2 +,…,+ Q8)= [0.552 (22.78) + 0.492(16.54) +,…,+ (-0.1752) (-10.46)] = 39.529
SS SCA= SS Crosses – SS GCA = 62.36 – 39.529 = 22.831
Stage 5. Split DF and SS of interaction crosses x environments (CxA)
DF GCA x A= (p-1)(a-1)= 7(2)= 14; DF SCA x A= DF C x A - DF GCA x A= 38 - 14= 24. Also: DF SCA x A= [(ps/2) - 1] (a-1) - (p-1)(a-1)= (aps/2) - a - (ps/2) + 1 - pa + p + a - 1= (aps/2) - (ps/2) - pa + p= p(as - s - 2a + 2p )/2 = p(a - 1)(s - 2 )/2= 8(2)(3)/2= 24. To split SS (C x A), Qik and (gl)ik must first be calculated as: ; .
For environment k= 1, the correction factor, CFA1= 2(Y..1.)/ps= 2(546.8)/40= 27.34. Q11= (Y131. - CFA1) + (Y141. - CFA1) + (Y151. - CFA1) + (Y161. - CFA1) + (Y171. - CFA1)= (27.48 - 27.34) + (29.8 - 27.34) + (26.88 - 27.34) + (29.84 - 27.34) + (29.32 - 27.34)= 6.62, Q21= 4.94; Q31= 2.14; Q41= 5.18; Q51= -7.06; Q61= -2.22; Q71= -5.7; Q81= -3.9; .
For environment k=2, the correction factor, CFA2= 2(Y..2.)/ps= 2(526.48)/40= 26.324. Q12= (Y132. - CFA2) + (Y142. - CFA2) + (Y152. - CFA2) + (Y162. - CFA2) + (Y172. - CFA2)= (23.92 - 26.324) + (28.68 - 26.324) + (27.84 - 26.324) + (27.96 - 26.324) + (26.28 - 26.324)= 3.06, Q22= 6.54; Q32= -8.34; Q42= 2.46; Q52= -3.38; Q62= -0.34; Q72= 3.66; Q82= -3.66; .
For environment k= 3, the correction factor, CFA3= 2(Y..3.)/ps= 2(712.72)/40= 35.636. Q13= (Y133. - CFA3) + (Y143. - CFA3) + (Y153. - CFA3) + (Y163. - CFA3) + (Y173. - CFA3)= (39.08 - 35.636) + (41.92 - 35.636) + (34.68 - 35.636) + (38.12 - 35.636) + (37.48 - 35.636)= 13.1, Q23= 5.06; Q33= -0.38; Q43= 7.02; Q53= -4.42; Q63= -8.02; Q73= -9.46; Q83= -2.9; , As: , then:
For trial 1
= -
-
=
For trial 2
= -
=
-
=
For trial 3
= -
=
-
=
Considering the above estimators, the following is calculated
SS GCAxA = =.
Dhillon (1978) developed the formulas for estimating
SS SCAxA=
Also, by statistical inference from the previous calculations, it deduced that: SS SCA x A = (SS CA1 + SS CA2 + SS CA3) - SS C - SS GCA x A = (SS Trat 1 - SS A - SS C) - SS GCA x A= SS CxA - SS GCA x A.
Thus, by approximation of the results that the above will generate, it must be obtained that: SS SCA x A= 31.897.
Stage 6. Obtain mean squares (MS)
MS A= SS A / (a-1)= 260.94/2= 130.47; MS Rep(A)= SS Rep(A)/a(r-1)= 45.625/9= 5.07; MS C= SS C/[(ps/2) - 1]= 62.35/19= 3.28; MS GCA= SS GCA/(p-1)= 39.529/7= 5.647; MS SCA= SS SCA /[p(s-2)/2]= 22.831/12= 1.90; MS C x A= SS C x A/(a-1)[(ps/2) - 1]= 51.09/38 = 1.34; MS GCA x A = SS GCA x A/(p-1)(a-1) = 19.925/14 = 1.37; MS SCA x A = SS SCA x A/[p(a-1)(s-2)]/2 = 31.89/24 = 1.32; MS Error = SS Error/{a(r-1)[(ps/2) - 1]}= 181.746/171= 1.06.
Stage 7. Calculate F values
In this section, reference should be made to the type of model selected (fixed, random, mixed) and based on this define the correct GLs and MSs to test the statistical hypotheses of interest (Sahagún, 1998). The F tests (Table 4) were proposed by Martínez (1983). F (GCA)= [MS GCA /(MS SCA + MS GCA x A - MS SCA x A)]= 2.94; F (SCA)= MS SCA/MS SCA x A= 1.44; F (GCA x A)= MS GCA x W/MS SCA x A= 1.01; F (SCA x A)= MS SCA x A/MS Error= 1.24.
Stage 8. Concentrate the calculations previously obtained in the Anova format
Table 4. Anova for grain yield for a partial diallel in a series of experiments.
Source of variation | Degrees of freedom | Sum of squares | Mean squares (MS) | F value | Expectation of mean squares (EMS) |
Environments(A) | 2 | 260.94 | 130.47 | ||
Rep(A) | 9 | 45.62 | 5.07 | ||
Crosses (C) | (19) | 62.35 | 3.28 | ||
GCA | 7 | 39.529 | 5.647 | 2.94 | σ2e+rσ2sp+[rs(p-2)/(p-1)] σ2gp+arσ2s+[ars(p-2)/(p-1)] σ2g |
SCA | 12 | 22.831 | 1.9 | 1.44 | σ2e + rσ2sp + arσ2s |
C x A | (38) | 51.09 | 1.34 | ||
GCA x A | 14 | 19.192 | 1.37 | 1.01 | σ2e+rσ2sp+[rs(p-2)/(p-1)] σ2gp |
SCA x A | 24 | 31.89 | 1.32 | 1.24 | σ2e + rσ2sp |
Error | 171 | 181.746 | 1.06 | σ2e | |
Total | 239 | 601.75 |
Application of the Opstat Software
The software is freely available at https://14.139.232.166/opstat. This analyzes a partial diallel cross based on a circulating sample (Kempthorne and Curnow, 1961). To create the database on its web page, the crosses are ordered in the rows and the repetitions in the columns, the latter delimited by spaces (*.prn) or by tabs (*.txt); between rows there are no additional spaces. If this is done from Microsoft Excel, the file will have an extension *.prn or *.txt. The labels on the first row will correspond to crosses, R1, R2, ..., Rn, the latter are repetitions. Each cross could be identified as 1x3, 1x4, 1x5, ..., 6x8. When pasting the data on the web page, the labels are not included. If the parents are included, they are captured below the last cross, as 1x1, 2x2, pxp (Sheoran et al., 1998).
To send the data to the Opstat platform, submit is selected; the software will request number of parents, number of repetitions, and sample size. Press Analyse. The output, for a single trial, includes (Sheoran et al., 1998; Jasso et al., 2022): a) Anova for a randomized complete block design, b) arithmetic mean and standard error for each cross, c) gi estimators for each parent, d) Anova with the breakdown of the effects between crosses in GCA and SCA, e) estimates of variances of GCA, SCA, additive, dominant and average and, f) standard error to compare gi values, and g) estimation of narrow-sense heritability.
Analyses of variance obtained with Opstat
To generate the series of experiments, the analysis of variance for each environment and the corresponding to the table crosses x environments must be performed.
To split the SS (C x A), the following is calculated
SS SCA x A = (SS SCAA1 + SS SCAA2 + SS SCAA3) - SS SCA= (18.892 + 11.458 + 24.599) - 22.696= 32.253. By subtraction, one obtains: SS GCA x A= SS C x A - SS SCA x A= 51.09 - 32.253= 18.837. Both calculations are approximate to those obtained with other methods.
The first three sums of squares for SCA are obtained from individual analyses of variance (A1, A2, A3; Tables 5, 6, 7); when considering the fourth sum of squares (Table 8), it must be corrected by multiplying it by r= 4, because the table of values crosses x environments was built by adding over the four repetitions that are in each environment.
Table 5. Analysis of variance for environment 1.
Source of variation | Degrees of freedom | Sum of squares | Mean squares | F value | p> F |
Repetitions | 3 | 37.605 | 12.535 | ||
Crosses | (19) | 34.819 | 1.833 | 2.259 | 0.00938 |
GCA | 7 | 15.927 | 2.275 | 2.805 | 0.014 |
SCA | 12 | 18.892 | 1.574 | 1.941 | 0.0481 |
Error | 57 | 46.241 | 0.811 | ||
Total | 79 | 118.665 |
Table 6. Analysis of variance for environment 2.
Source of variation | Degrees of freedom | Sum of squares | Mean squares | F value | p> F |
Repetitions | 3 | 6.338 | 2.113 | ||
Crosses | (19) | 20.098 | 1.058 | 0.98 | 0.496 |
GCA | 7 | 8.64 | 1.234 | 1.143 | 0.349 |
SCA | 12 | 11.458 | 0.955 | 0.884 | 0.567 |
Error | 57 | 61.536 | 1.08 | ||
Total | 79 | 87.972 |
Table 7. Analysis of variance for environment 3.
Source of variation | Degrees of freedom | Sum of squares | Mean squares | F value | p > F |
Repetitions | 3 | 1.922 | 0.641 | ||
Crosses | (19) | 59.351 | 3.124 | 2.362 | 0.00653 |
GCA | 7 | 34.752 | 4.965 | 3.754 | 0.00207 |
SCA | 12 | 24.599 | 2.05 | 1.550 | 0.13339 |
Error | 57 | 75.372 | 1.322 | ||
Total | 79 | 136.644 |
Table 8. Analysis of variance to break down SS (CxA).
Source of variation | Degrees of freedom | Sum of squares | Mean squares | F value | p > F |
Repetitions | 2 | 65.236 | 32.618 | ||
Crosses | (19) | (15.587) | 0.82 | 2.441 | 0.00945 |
GCA | 7 | 9.914 | 1.416 | 4.214 | 0.00159 |
SCA | 12 | 5.674 | 0.473 | 1.407 | 0.20534 |
Error | 38 | 12.771 | 0.336 | ||
Total | 59 | 93.594 |
In this last table, repetitions=environments, error= C x A, Total= Trat 1= SS A + SS C + SS C x A; each source of variation must be multiplied by 4 (number of repetitions) and F values must be obtained by applying the procedures described by Martínez (1991) or Dhillon (1978), among others (Table 4).
The procedures described for a single environment were also referenced by Singh and Chauhdary (1985); the artifices implemented in the present study to be analyzed with Opstat can also be applied to the analysis of a partial diallel cross corresponding to the methodologies proposed by Fyfe and Gilbert (1963); Federer (1967); Narain et al. (1974), as suggested by Dhillon (1978); Martínez (1991).
Conclusions
The analysis of a partial diallel cross is very laborious when using a desktop calculator; this situation will be more critical when increasing p and s in the trial or when several agronomic characteristics and more years, localities or both are considered in the series of experiments. To save time and resources, a matrix calculator or Opstat, available for free on their websites, should be used. To complete the Anova table in the series of experiments, the data contained in a table of values crossed x environments, averaged over repetitions, or averaged over environments, must be entered as if analyzing a single environment; for the second option, the output will correspond to a partition of effects Trat 1= SS A + SS C + SS (CxA); in this, Opstat produces the SS of GCA and the SS of SCA in an easy and reliable way, information that, additionally, allows calculating the sum of squares of the interactions GCA x A and SCA x A, using some of the recommendations suggested in this study.
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